WebThe line x +2y= 9 intersects the curve xy +18= 0 at the points A and B. Find the coordinates of Aand B. summer 2002/Pl/Ql WebThe point of intersection is (2, 1). Next, use the following formula, with which you may not be familiar: Distance = (Ax0 + By0 + C) / √ (A^2 + B^2), where (x0, y0) are the coordinates of the point, and A, B, and C are the coefficients of the equation of the line in standard form (such as here, luckily!).
The shortest distance between the line x – y = 1 and the curve x^2 = 2y ...
Web10 mrt. 2014 · A key to easily solving this is lab bhattacharjee's observation that x 2 + x y − 2 y 2 = ( x + 2 y) ( x − y). Therefore, the curve is the union of the lines L 1: x + 2 y = 0 … WebThe line x 2y = 2 intersects the curve x + y 2 = 10 at two points A and B. Find the equation of the perpendicular bisector of the line AB. The line x – 2y = 2 intersects the curve x + … lidl non bio washing powder
47.The line that is normal to the curve x^2+2xy-3y^2=0at(1,1 ...
WebThe line y = x + 2 cuts the curve 2x^2 + y ^2 = 5xy + 8 at A and B. What are the coordinates of the midpoint of AB? Solution: 2x^2 + y ^2 = 5xy + 8 or 2x^2 + y ^2 - 5xy = 8 … (1) y = x+2 … (2) Putting the value of y from (2) into (1): 2x^2 + (x+2)^2 -5x (x+2) = 8, or 2x^2 + x^2 + 4x + 4 - 5x^2 - 10x = 8, or -2x^2 - 6x = 4, or x^2 + 3x = -2, or WebEquation of the curve is x 2 + 2 y 2 = 2 ⇒ x 2 2 + y 2 1 = 1. Equation of the line is x + y = 1 ; y = 1-x. Solving the above two equations. x 2 +2 1 - x 2 =2 x 2 + 2 x 2 + 2 − 4 x = 2 3 x … WebThe equation of a line is y = x − k, where k is a constant, and the equation of a curve is x² + 2y = k. a) When k = 1, the line intersects the curve at the points A and B. Find the coordinates of A and the coordinates of B. b) Find the value of k for which the line y = x − k is a tangent to the curve x² + 2y = k. mclaughlin schools