Web10 Aug 2024 · I need to be able to calculate the initial velocity required to reach a height at a given amount of seconds after firing. I know the initial velocity ignoring setting the travel time is: v 0 = 2 g h where g - gravity - could be other than 9.81 m / s 2 h - maximum height to reach t - time to reach height, already known Web28 Apr 2016 · A rocket is launched from the top of a 50 foot cliff with an initial velocity of 120 feet per second. The height, h, of the rocket after t seconds is given by the equation h=-16t^2 + 120t+ 50. How long after the rocket is launched will it be 10 feet from the ground? asked by Anonymous April 28, 2016 1 answer just solve for t in
g-force - Wikipedia
WebT is just a designator for the main sequence countdown time that serves as the synchronisation device for the majority of systems and procedures that have to take place … http://ktaylorsmathclass.weebly.com/uploads/2/2/7/3/22738894/quadratic_word_problems-solving_f2015cn.pdf burlington vt free press obits
h=-16t^2+48t describes the rocket
Web30 Apr 2024 · (ii) How many seconds was the rocket airborne after its fuel was exhausted. The maximum height of the rocket is 1444feet, and the rocket's airborne time is 17sec. … Webzero of a function: (noun) a value of the independent variable in a function that results in a value of zero for the dependent variable. zero product property : (noun) the property … WebThe equation for the object's height s at time t seconds after launch is s(t) = −4.9t 2 + 19.6t + 58.8, where s is in meters. When does the object strike the ground? ... So the object is at … halstead place south shields